3x^2-2x=-5x^2-3x

Solution for 3x^2-2x=-5x^2-3x equation:

3x^2-2x=-5x^2-3x

We move all terms to the left:

3x^2-2x-(-5x^2-3x)=0

We get rid of parentheses

3x^2+5x^2+3x-2x=0

We add all the numbers together, and all the variables

8x^2+x=0

a = 8; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·8·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*8}=\frac{-2}{16}
=-1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*8}=\frac{0}{16}
=0
$